Problems on Ages Questions Answers

  • 1. Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is

    1. 90
    2. 98
    3. 120
    4. Data is not adequate
    Answer :

    Option D

  • 2. Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages

    1. 30
    2. 35
    3. 37
    4. 41
    Answer :

    Option B

    Explanation:

    Let A's age 10 years ago = x years.
    Then, B's age 10 years ago = 2x years.
    (x + 10) / (2x+ lO) = 3/4
    => x = 5.
    So, the total of their present ages =(x + 10 + 2x + 10)
    = (3x + 20) = 35 years.

  • 3. Total of the ages of A, B ahd C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2: 3. What is the age of B at present

    1. 25
    2. 30
    3. 45
    4. 60
    Answer :

    Option B

    Explanation:

    Let their ages 10 years ago is x, 2x and 3x years.
    10 + 2x + 10 + 3x + 10 = 90 hence x= 10
    B’s present age = (2x + 10) =30 years

  • 4. The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be

    1. 15 years
    2. 18 years
    3. 20 years
    4. 22 years
    Answer :

    Option C

    Explanation:

    Clue : (60 - x) - 6 = 5(x - 6)

  • 5. Six years ago, the ratio of the ages of Kunal and Sagar was 6:5, Four years hence, the ratio of their ages will be 11:10. What is Sagar age at present

    1. 10 years
    2. 12 years
    3. 14 years
    4. 16 years
    Answer :

    Option D

    Explanation:

    Let six years ago the age of Kunal and Sagar are 6x and 5x resp.
    then,
    \begin{aligned}
    => \frac{(6x+6)+4}{(5x+6)+4} = \frac{11}{10}
    \end{aligned}
    \begin{aligned}
    <=> 10(6x+10) = 11(5x+10)
    \end{aligned}
    \begin{aligned}
    <=> 5x = 10 => x = 2
    \end{aligned}

    So Sagar age is (5x+6) = 16

  • 6. The ages of two persons differ by 20 years. If 5 years ago, the elder one be 5 times as old as the younger one, their present ages (in years) are respectively

    1. 20,20
    2. 20,10
    3. 25,15
    4. 30,10
    Answer :

    Option D

    Explanation:

    Let their ages be x and (x + 20) years.
    5 (x - 5) = (x + 20 - 5) or 4x = 40 or x = 10.
    Their present ages are 30 years and 10 years

  • 7. Sachin is younger than Rahul by 7 years. If the ratio of their ages is 7:9, find the age of Sachin

    1. 23.5
    2. 24.5
    3. 12.5
    4. 14.5
    Answer :

    Option B

    Explanation:

    If Rahul age is x, then Sachin age is x-7,
    so (x-7)/x = 7/9
    => 9x-63 = 7x
    => 2x = 63
    => x = 31.5

    So Sachin age is 31.5 - 7 = 24.5

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