Problems on Ages Questions Answers

  • 8. The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person

    1. 15
    2. 20
    3. 25
    4. 30
    5. 24%
    6. 28%
    7. 32%
    8. 36%
    Answer :

    Option F

    Explanation:

    Let's take the present age of the elder person = x
    and the present age of the younger person = x – 16
    (x – 6) = 3 (x-16-6)
    => x – 6 = 3x – 66
    => 2x = 60
    => x = 60/2 = 30

  • 9. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is

    1. 20 years
    2. 21 years
    3. 22 years
    4. 24 years
    Answer :

    Option C

    Explanation:

    Let the son's present age be x years. Then, man's present age = (x + 24) years
    => (x + 24) + 2 = 2(x + 2)
    => x + 26 = 2x + 4
    So, x = 22

  • 10. Ratio of ages of three persons is 4:7:9, Eight years ago, the sum of their ages was 56. Find their present ages.

    1. 16,35,36
    2. 12,28,36
    3. 16,28,27
    4. 16,28,36
    Answer :

    Option D

    Explanation:

    Let the present ages are 4x, 7x, 9x.
    => (4x-8) + (7x-8) + (9x-8) = 56
    => 20x = 80
    => x = 4

    So their present ages are: 16,28,36

  • 11. Raju age after 15 years will be 5 times his age 5 years back, What is the present age of Raju

    1. 15
    2. 14
    3. 10
    4. 8
    Answer :

    Option C

    Explanation:

    Clearly,
    x+15 = 5(x-5)
    <=> 4x = 40 => x = 10

  • 12. Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age

    1. 12,28
    2. 14,30
    3. 16,32
    4. 18,34
    Answer :

    Option B

    Explanation:

    Let the age of younger person is x,
    Then elder person age is (x+16)
    => 3(x-6) = (x+16-6) [6 years before]
    => 3x-18 = x+10
    => x = 14.
    So other person age is x + 16 = 30

  • 13. The sum of the ages of a father and son is 45 years. Five years ago, the product of their ages was four times the fathers age at that time. The present age of father and son

    1. 34,11
    2. 35,10
    3. 36,9
    4. 40,5
    Answer :

    Option C

    Explanation:

    Let sons age = x years. Then fathers age = (45 - x)years.
    (x—5)(45—x—5) = 4(45- x - 5) hence (x—5) = 4 so x = 9
    Their ages are 36 years and 9 years.

  • 14. Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages

    1. 35
    2. 34
    3. 45
    4. 25
    Answer :

    Option A

    Explanation:

    Let the present age of P and Q be 3x and 4x respectively.
    Ten years ago, P was half of Q in age
    => 2(3x – 10) = (4x – 10)

    => 6x – 20 = 4x – 10

    => 2x = 10

    => x = 5

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