Percentage Problems and Solutions

  • 22. 2 is what percent of 50

    1. 2%
    2. 4%
    3. 6%
    4. 8%
    Answer :

    Option B

    Explanation:

    2/50 * 100 = 1/25 * 100 = 4 %

  • 23. A student multiplied a number by 3/5 instead of 5/3. What is the percentage error.

    1. 64%
    2. 65%
    3. 66%
    4. 67%
    Answer :

    Option A

    Explanation:

    Let the number be x,
    then,
    \begin{aligned}
    \frac{5}{3} - \frac{3}{5} = \frac{16}{15}x
    \end{aligned}

    Error% = \begin{aligned}
    (\frac{16}{15}x * \frac{3}{5} * 100)% = 64%
    \end{aligned}

  • 24. How many litres of pure acid are there in 8 litres of a 20% solution

    1. 1.5
    2. 1.6
    3. 1.7
    4. 1.8
    5. Only argument I is strong
    6. Only argument II is strong
    7. Either I or II is strong
    8. Neither I nor II is strong
    9. Both I and II are strong
    Answer :

    Option F

    Explanation:

    Question of this type looks a bit typical, but it is too simple, as below...

    It will be 8 * 20/100 = 1.6

  • 25. What will be the fraction of 20%

    1. 1/4
    2. 1/5
    3. 1/10
    4. None of above
    Answer :

    Option B

    Explanation:

    It will 20*1/100 = 1/5

  • 26. Two numbers are less than third number by 30% and 37% respectively. How much percent is the second number less than by the first

    1. 8%
    2. 9%
    3. 10%
    4. 11%
    Answer :

    Option C

    Explanation:

    Let the third number is x.
    then first number = (100-30)% of x
    = 70% of x = 7x/10

    Second number is (63x/100)

    Difference = 7x/10 - 63x/100 = 7x/10

    So required percentage is, difference is what percent of first number

    => (7x/100 * 10/7x * 100 )% = 10%

  • 27. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are

    1. 42,30
    2. 42,31
    3. 42,32
    4. 42,33
    Answer :

    Option D

    Explanation:

    Let their marks be (x+9) and x.
    Then, x+9 = 56/100(x + 9 +x)
    => 25(x+9)
    => 14 (2x + 9)
    => 3x = 99
    => x = 33.
    So, their marks are 42 and 33

  • 28. If number x is 10% less than another number y and y is 10% more than 125, then find out the value of x

    1. 123.55
    2. 123.65
    3. 123.75
    4. 123.85
    Answer :

    Option C

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