Percentage Problems and Solutions

• 8. 2.09 can be expressed in terms of percentage as

  1. 0.25
  2. 1.15
  3. 1.25
  4. 1.35
  5. 2.09%
  6. 20.9%
  7. 209%
  8. 0.209%

  Answer :

  Option

  Explanation:

  While calculation in terms of percentage we need to multiply by 100, so
  2.09 * 100 = 209.

• 9. One fourth of one third of two fifth of a number is 15. What will be40% of that number

  1. 140
  2. 150
  3. 180
  4. 200

  Answer :

  Option C

  Explanation:

  (1/4) * (1/3) * (2/5) * x = 15 then x = 15 * 30 = 450
  40% of 450 = 180

• 10. 10% of inhabitants of a village having died of cholera, a panic set in, during which 25% of the remaining inhabitants let the village. The population is then reduced to 4050. Find the original inhabitants

  1. 5500
  2. 6000
  3. 6500
  4. 7000

  Answer :

  Option B

  Explanation:

  Let the total number is x,
  then,
  
  (100-25)% of (100 - 10)% x = 4050
  => 75% of 90% of x = 4050
  => 75/100 * 90/100 * x = 4050
  => x = (4050*50)/27 = 6000
  

• 11. Out of 450 students of a school, 325 play football, 175 play cricket and 50 neither play football nor cricket. How many students play both football and cricket ?

  1. 75
  2. 100
  3. 125
  4. 150

  Answer :

  Option B

  Explanation:

  Students who play cricket, n(A) = 325
  Students who play football, n(B) = 175
  Total students who play either or both games,
  \begin{aligned}
  = n(A\cup B) = 450-50 = 400\\
  \text{Required Number}, n(A \cap B) \\
  = n(A)+n(B)-n(A\cup B) \\
  = 325 + 175 - 400 = 100
  \end{aligned}

• 12. In an examination, 34% of the students failed in mathematics and 42% failed in English. If 20% of the students failed in both the subjects, then find the percentage of students who passed in both the subjects.

  1. 40%
  2. 42%
  3. 44%
  4. 46%

  Answer :

  Option C

  Explanation:

  Failed in mathematics, n(A) = 34
  Failed in English, n(B) = 42
  \begin{aligned}
  n(A\cup B) = n(A)+n(B)-n(A\cap B) \\
  = 34+42-20 = 56 \\
  \text{Failed in either or both subjects are 56} \\
  \text{Percentage passed = }(100-56)\% \\
  = 44\%
  \end{aligned}
  

• 13. A housewife saved Rs. 2.50 in buying an item on sale. If she spent Rs. 25 for the item, approximately how much percent she saved in the transaction

  1. 9%
  2. 10%
  3. 11%
  4. 12%

  Answer :

  Option A

  Explanation:

  Actual Price = Rs.25 + Rs.2.50 = Rs.27.5
  
  Saving = Rs.2.5
  
  \begin{aligned}\text{Percentage Saving = }\dfrac{2.5}{27.5}\times 100 \\
  = \dfrac{250}{27.5} = \dfrac{2500}{275}\\
  = \dfrac{100}{11} = 9\dfrac{1}{11}\% \approx 9\%\end{aligned}

• 14. What will be the fraction of 4%

  1. 1/20
  2. 1/50
  3. 1/75
  4. 1/25

  Answer :

  Option D

  Explanation:

  4*1/100 = 1/25.
  
  Friends I know it is quite simple, but trust me while solving percentage questions in Hurry we use to do these types of mistake only. So I recommend you to have a bit practise of this.