Trains Problems Questions Answers

  • 15. A train is moving at a speed of 132 km/hour. If the length of the train is 110 meters, how long will it take to cross a railway platform 165 meters long.

    1. 7 second
    2. 7.5 second
    3. 8 second
    4. 8.5 second
    5. Only assumption I is implicit
    6. Only assumption II is implicit
    7. Either I or II is implicit
    8. Neither I nor II is implicit
    9. Both I and II are implicit
    Answer :

    Option E

    Explanation:

    As we need to calculate answer in seconds, so first convert speed into meter/sec.

    we know 1 km/hr = 1*(5/18) m/sec
    So, Speed = 132* (5/18) = 110/3 m/sec

    Distance need to be covered in passing the platform =
    Length of train + length of platform = 110 + 165
    = 275 meters

    Time = Distance/Speed

    \begin{aligned}
    => Time = 275* \frac{3}{110} = \frac{15}{2} \\
    = 7.5 seconds
    \end{aligned}

  • 16. In what time will a train 100 meters long cross an electric pole, if its speed is 144 km/hr

    1. 5 seconds
    2. 4.5 seconds
    3. 3 seconds
    4. 2.5 seconds
    Answer :

    Option D

    Explanation:

    First convert speed into m/sec

    Speed = 144*(5/18) = 40 m/sec

    Time = Distance/speed
    = 100/40 = 2.5 seconds

  • 17. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is ?

    1. 1:3
    2. 3:2
    3. 3:5
    4. 3:7
    Answer :

    Option B

    Explanation:

    Let the speeds of the two trains be x m/sec and y m/sec respectively.

    Then, length of the first train = 27x metres,
    Length of the second train = 17y metres.
    [because distance = speed*time]

    \begin{aligned}
    \frac{27x+17y}{x+y} = 23 \\
    => 27x + 17y = 23x + 23y \\
    => 4x = 6y \\
    => \frac{x}{y} = \frac{6}{4}
    \end{aligned}
    So ratio of the speeds of train is 3:2

  • 18. Two trains 140 metre and 160 metre long run at the speed of 60 km/hr and 40 km/hr respectively in opposite direction on parallel tracks. What time these will take to cross each other ?

    1. 10.7 Seconds
    2. 10.8 Seconds
    3. 10.9 Seconds
    4. 11.8 Seconds
    Answer :

    Option B

    Explanation:

    Relative Speed = 60+40 = 100 Kmph
    = 100*(5/18) = 250/9 m/sec

    Distance to be covered = 140 + 160 = 300 metres

    Time = Distance/Speed

    \begin{aligned}
    Time = 300*\frac{9}{250} \\
    = \frac{54}{5} = 10.8\text{ seconds}
    \end{aligned}

  • 19. How long does a train 110 meters long running at the speed of 72 km/hour take to cross a bridge 132 meters in length ?

    1. 15 seconds
    2. 12.1 seconds
    3. 10 seconds
    4. 8.1 seconds
    Answer :

    Option B

    Explanation:

    Speed = 72 km/hour = 72*(5/18) m/sec
    = 20 m/sec

    Total distance to be covered = 110+132 = 142 meters

    Time = Distance/Speed
    = 242/20 = 12.1 seconds

  • 20. Speed of a goods train is 72 km/hr. This train crosses a 250 meter platform in 26 seconds. Then find the length of goods train.

    1. 250 meters
    2. 260 meters
    3. 270 meters
    4. 280 meters
    Answer :

    Option C

    Explanation:

    First convert speed from km/hr to m/sec

    So, Speed = 72*(5/18) = 20 m/sec
    Time = 26 seconds

    Let the length of the train be x meters.
    We know, Distance = Speed*Time.
    [you can remember this formula as remembering DUST = D*ST... Distance=Speed*Time]

    x+250 = 20*26
    => x = 270 meters

    So length of the goods train is 270 meter

  • 21. Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other, is

    1. 9.8 seconds
    2. 10.8 seconds
    3. 11.8 seconds
    4. 12.8 seconds
    Answer :

    Option B

    Explanation:

    Relative Speed = 60+40 = 100 kmph
    = 100*(5/18) = 250/9 m/sec

    Distance = 140+160 = 300 meters

    Time = Distance/Speed

    \begin{aligned}
    300*\frac{9}{250} = \frac{54}{5} \\
    = 10.8 \text{ seconds}
    \end{aligned}

    So the time trains will take to cross each other will be 10.8 seconds

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