Table Charts Questions Answers

• 1. What is the average amount of interest per year which the company had to pay during this period ?

  1. Rs. 36.66 lakhs
  2. Rs. 36.36 lakhs
  3. Rs. 36.26 lakhs
  4. Rs. 36.06 lakhs

  Answer :

  Option A

  Explanation:

  Average amount of interest paid by the Company during the given period will be
  \begin{aligned}
  \frac{23.4 + 32.5 + 41.6 + 36.4 + 49.4}{5} lakh \\
  = 36.66 lakhs
  \end{aligned}

• 2. The total amount of bonus paid by the company during the given period is approximately what percent of the total amount of salary paid during this period ?

  1. .5%
  2. 1%
  3. 1.5%
  4. 2%

  Answer :

  Option B

  Explanation:

  Here we simply need to calculate that bonus is what percent of salary.
  We will just sum all bonus and salary to get the percentage as below,
  \begin{aligned}
  \left(\frac{3.00 + 2.52 + 3.84 + 3.68 + 3.96}{288 + 342 + 324 + 336 + 420}*100\right)\% \\
  = \left(\frac{17}{1710}*100\right)\% \\
  = 1\% \text{approx.}
  \end{aligned}

• 3. Total expenditure on all these items in 1998 was approximately what percent of the total expenditure in 2002 ?
  
  

  1. 61%
  2. 47%
  3. 59%
  4. 69%

  Answer :

  Option D

  Explanation:

  Required percentage we can easily calculate from the above table chart.
  Required percentage will be,
  \begin{aligned}
  \left(\frac{288 + 98 + 3.00 + 23.4 + 83}{420 + 142 + 3.96 + 49.4 + 98}*100\right)\% \\
  = \left(\frac{495.4}{713.36}*100\right)\% \\
  = 69.45\%
  \end{aligned}

• 4. Calculate the total expenditure of the company over these items during the year 2000 from the table chart given.
  
  

  1. Rs. 543.44 lakhs
  2. Rs. 544.44 lakhs
  3. Rs. 545.44 lakhs
  4. Rs. 546.44 lakhs

  Answer :

  Option B

  Explanation:

  Total expenditure of the Company during 2000
  
  = Rs. (324 + 101 + 3.84 + 41.6 + 74) lakhs
  
  = Rs. 544.44 lakhs.
  
  

• 5. The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately?

  1. 4:13
  2. 7:13
  3. 10:13
  4. 11:13

  Answer :

  Option C

  Explanation:

  Required Ratio will be
  \begin{aligned}
  \left( \frac{83 + 108 + 74 + 88 + 98}{98 + 112 + 101 + 133 + 142} \right) \\
  = \left( \frac{451}{586} \right) \\
  = \frac{1}{1.3}
  = \frac{10}{13}
  \end{aligned}