HCF and LCM Problems and Solutions

  • 15. Reduce \begin{aligned}
    \frac{368}{575}
    \end{aligned} to the lowest terms.

    1. \begin{aligned} \frac{30}{25} \end{aligned}
    2. \begin{aligned} \frac{28}{29} \end{aligned}
    3. \begin{aligned} \frac{28}{29} \end{aligned}
    4. \begin{aligned} \frac{16}{25} \end{aligned}
    Answer :

    Option D

    Explanation:

    We can do it easily by in two steps
    Step1: We get the HCF of 368 and 575 which is 23
    Step2: Divide both by 23, we will get the answer 16/25

  • 16. Find the HCF of \begin{aligned} \frac{2}{3}, \frac{4}{6}, \frac{8}{27} \end{aligned}

    1. \begin{aligned} \frac{2}{27} \end{aligned}
    2. \begin{aligned} \frac{8}{3} \end{aligned}
    3. \begin{aligned} \frac{2}{3} \end{aligned}
    4. \begin{aligned} \frac{8}{27} \end{aligned}
    Answer :

    Option A

    Explanation:

    Whenever we have to solve this sort of question, remember the formula.
    HCF = \begin{aligned} \frac{HCF of Numerators}{LCM of Denominators} \end{aligned}
    So answers will be option 1

  • 17. The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is

    1. 48
    2. 22
    3. 56
    4. 27
    Answer :

    Option A

    Explanation:

    Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
    So, the numbers 12 and 16.
    L.C.M. of 12 and 16 = 48.

  • 18. LCM of two numbers is 7700 and HCF is 11. If one number is 308 then other number is

    1. 269
    2. 285
    3. 300
    4. 275
    Answer :

    Option D

  • 19. Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively

    1. 125
    2. 127
    3. 129
    4. 131
    Answer :

    Option B

    Explanation:

    In this type of question, its obvious we need to calculate the HCF, trick is
    HCF of (1661 - 10) and (2045 -13)
    = HCF (1651, 2032) = 127

  • 20. Find the largest number which divides 62,132,237 to leave the same reminder

    1. 30
    2. 32
    3. 35
    4. 45
    Answer :

    Option C

    Explanation:

    Trick is HCF of (237-132), (132-62), (237-62)
    = HCF of (70,105,175) = 35

  • 21. Find the largest number of four digits which is exactly divisible by 27,18,12,15

    1. 9700
    2. 9710
    3. 9720
    4. 9730
    Answer :

    Option C

    Explanation:

    LCM of 27-18-12-15 is 540.
    After dividing 9999 by 540 we get 279 remainder.
    So answer will be 9999-279 = 9720

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