Direction Sense Test Questions Answers

  • 8. One day, Raviraj left home and cycled 20 Km southwards, turned right and cycled 10 km and turned right and cycled 20 Km and turned left and cycled 20 Km. How many kilometres will he have to cycle to reach his home straight ?

    1. 50 Km
    2. 30 Km
    3. 40 Km
    4. 60 Km
    Answer :

    Option B

    Explanation:

    Please refer to explanation image,
    Raviraj starts from home at A, moves 20 Km in south upto B. Then he turns right and moves 10 Km upto C, then he turns right and moves 20 Km upto D, then he turns lefts and moves 20 Km upto E.

    So from image it is clear that, if he moves straight then he will have to move AD+DE, AD = BC = 10 Km
    So, he will have to move 10 + 20 = 30 Km

  • 9. I am facing South. I turn right and walk 20 metre. Then I turn right again and walk 10 metre. Then I turn left and walk 10 metre and then turning right walk 20 metre. Then I turn right again and walk 60 metre. In which direction am I from the starting point ?

    1. North-East
    2. Norst-West
    3. North
    4. West
    Answer :

    Option A

    Explanation:

    Please refer to figure for the movements.
    Final direction will be north-east with reference to the starting position.

  • 10. A child is looking for his father. He went 90 meters in the east before turning to his right. He went 20 meters before turning to is right again to look for his father at his uncle's place 30 meters from this point. His father was not there. From there, he went 100 meters to his north before meeting his father in a street. How far did the son meet his father from starting point ?

    1. 80 metre
    2. 90 metre
    3. 100 metre
    4. 110 metre
    Answer :

    Option C

    Explanation:

    Clearly, the child moves from A to B 90 metres eastwards upto B, then turns right and moves 20 metre upto C, then turns right and moves upto 30 metre upto D. Finally he turns right and moves upto 100 metre upto E.

    So AB = 90 metre, BF = CD = 30 metre,
    So, AF = AB - BF = 60 metre

    Also DE = 100 metre, DF = BC = 20 metre
    So, EF = DE - DF = 80 metre

    as we can see in image that triangle AFE is a right angled triangle and we are having two sides, need to calculate third one, so we can apply Pythagoras theorem here

    \begin{aligned}
    A = AE = \sqrt{AF^2 + EF^2} \\
    = \sqrt{(60)^2+(80)^2} \\
    = \sqrt{3600+6400} \\
    = \sqrt{10000} = 100
    \end{aligned}

    So from starting point his father was 100 metre away.

  • 11. Starting from a point P, Sachin walked 20 metres towards South. He turned left and walked 30 metres. He then turned left and walked 20 metres. He again turned left and walked 40 metres and reached a point Q. How far and in which direction is the point Q from the point P ?

    1. 30 metres, West
    2. 10 metres, West
    3. 30 metres, North
    4. 10 metres, North
    Answer :

    Option B

    Explanation:

    Please refer to the image for movements.

    Distance from the P to Q is 10 metres and direction of Q with reference to to P is west.

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