Coding Decoding Questions Answers

• 1. If COOL is coded as DQRP, then write the code for HOT

  1. JQW
  2. IQW
  3. IQX
  4. IPW

  Answer :

  Option B

  Explanation:

  In COOL, first letter is increased by 1, second by 2, third by 3 and so on.
  
  So HOT will be coded as,
  H+1 I
  O+2 Q
  T+3 W
  
  So it will be IQW

• 2. In a certain code, TRIPPLE is written as SQHOOKD. How is DISPOSE written in that code ?

  1. EJTQPTF
  2. EJTQPTG
  3. CHRPNRD
  4. CHRONRD

  Answer :

  Option D

  Explanation:

  Clearly every letter is decreased by 1.
  So DISPOSE will be CHRONRD

• 3. In a certain code, SIKKIM is written as THLJJL, how is TRAINING written in that code ?

  1. SQBHOHOF
  2. UQBHOIOF
  3. UQBHOHOI
  4. UQBHOHOF

  Answer :

  Option D

  Explanation:

  In given word, word is increasing and decreasing by one alternatively as,
  S +1 T
  I -1 H
  K +1 L
  K -1 J
  I +1 J
  M -1 L
  
  So in the same way TRAINING will be UQBHOHOF

• 4. If in a certain language, COUNSEL is coded as BITIRAK, how is GUIDANCE written in that code ?

  1. EOHYZJBB
  2. FOIYZJBB
  3. FOHYZJBB
  4. None of above

  Answer :

  Option C

  Explanation:

  The letters at odd positions are each moved one step backward, while the letters at even positions are respectively moved six, five, four, three, two,... steps backward to obtain the corresponding letters of the code.

• 5. If TAP is coded as SZO, then how is FREEZE coded ?

  1. ATSSTS
  2. EQDDYD
  3. ESDDYD
  4. EQDDZD

  Answer :

  Option B

  Explanation:

  Clearly,
  
  T -1 = S
  A -1 = Z
  P -1 = O
  
  So FREEZE will be,
  
  F -1 E
  R -1 Q
  E -1 D
  E -1 D
  Z -1 Y
  E -1 D

• 6. In a certain code, MENTION is written as LNEITNO. How is PATTERN written in that code ?

  1. ATAETNR
  2. OTAETNR
  3. OTAESNR
  4. STAETNR

  Answer :

  Option B

  Explanation:

  In the given word, we can analyse that,
  M is decreased by 1, M-1 = L, and other words are interchanged,
  
  EN - NE
  TI - IT
  ON - NO
  
  So PATTERN will be
  
  P -1 O
  AT - TA
  TE - ET
  RN - NR
  

• 7. If JOSEPH is coded as FKOALD, then GEORGE will be coded as :

  1. CAKNCA
  2. HAKNCA
  3. CBKNCA
  4. CALNCA

  Answer :

  Option A

  Explanation:

  Each letter of the word is moved four step back to decode it.
  So GEORGE will be CAKNCA