Bar Charts Questions Answers

• 1. What is the difference between the production of Company Z in 1998 and Company Y in 1996 ?
  
  

  1. 10,00,000 tonnes
  2. 15,00,000 tonnes
  3. 20,00,000 tonnes
  4. 25,00,000 tonnes

  Answer :

  Option C

  Explanation:

  As per bar chart, Difference will be
  [45-25]*100000 = 20,00,000 tonnes
  
  Please note: we multiplied it by 100000, because graph is given in "lakh" tonnes
  
  

• 2. What is the ratio of the average production of Company X in the period 1998-2000 to the average production of company Y in the same period
  
  

  1. 23:25
  2. 24:27
  3. 25:26
  4. 27:29

  Answer :

  Option A

  Explanation:

  Average production of Company X in the period 1998-2000
  =[13∗(25+50+40)]=(1153)lakh tonnes
  \begin{aligned}
  = \left[ \frac{1}{3}*(25+50+40) \right] \\
  = \left(\frac{115}{3} \right) \text{lakh tonnes} \\
  \end{aligned}
  Average Production of company Y in the period 1998-2000
  =[13∗(35+40+50)]=(1253)lakh tonnesRequired Ratio =11531253=115125=2325=23:25
  \begin{aligned}
  = \left[ \frac{1}{3}*(35+40+50) \right] \\
  = \left(\frac{125}{3} \right) \text{lakh tonnes} \\
  \text{Required Ratio =} \\
  \frac{\frac{115}{3}}{\frac{125}{3}} \\
  = \frac{115}{125} \\
  = \frac{23}{25} \\
  = 23:25
  
  \end{aligned}

• 3. The average production for five years was maximum for which Company ?
  
  

  1. 2000
  2. 1999
  3. 1997
  4. 1998

  Answer :

  Option C

  Explanation:

  Percentage change(rise/fall) in the production of Y in comparison to the previous year, for different years are:
  \begin{aligned}
  \text{for 1997 =}\left[\frac{(35-25)}{25}*100 \right] \\
  = 40 \% \\
  
  \text{for 1998 =}\left[\frac{(35-35)}{35}*100 \right] \\
  = 0 \% \\
  
  \text{for 1999 =}\left[\frac{(40-35)}{35}*100 \right] \\
  = 14.29 \% \\
  
  \text{for 2000 =}\left[\frac{(50-40)}{40}*100 \right] \\
  = 25 \% \\
  
  \end{aligned}
  So maximum percentage is for year 1997
  
  

• 4. What is the percentage increase in the production of Company Y from 1996 to 1999 ?
  
  

  1. 40%
  2. 50%
  3. 55%
  4. 60%

  Answer :

  Option D

  Explanation:

  To get the percentage increase in the something, we have to first get the difference between the final value and initial value, then we can get the calculate that difference is what percentage of "initial value"
  
  So lets solve it,
  
  Percentage increase in the production of Company Y from 1996 to 1999
  =[40−2525∗100]%=[1525∗100]%=60%
  \begin{aligned}
  =\left[ \frac{40-25}{25}*100 \right]\% \\
  =\left[ \frac{15}{25}*100 \right]\% \\
  = 60 \%
  \end{aligned}

• 5. The average production for five years was maximum for which Company ?
  
  

  1. X
  2. Y
  3. Z
  4. X and Z

  Answer :

  Option D

  Explanation:

  Average production in (lakh tonnes) for three companies are:
  Company X = (1/5)(30+45+25+50+40)
  = 190/5 = 38
  
  Similarly for Y it is 37 and for Z it is 38
  
  So for X and Z it is equal and maximum
  
  

• 6. In which year the percentage of production of Company Z to the production of company Y is maximum ?
  
  

  1. 1998
  2. 1996
  3. 2000
  4. 1999

  Answer :

  Option B

  Explanation:

  The percentages of production of Company Z to the production of Company Y in various years is as:
  Note: Small thing which should always be taken care of, is to find percentage of which company to which company, I mean the order. As in this question
  Company Z to the Company Y.
  So lets solve it,
  
  
  for 1996 =(3525∗100)%=140%for 1997 =(4035∗100)%=114.29%for 1998 =(4535∗100)%=128.57%for 1999 =(3540∗100)%=87.5%for 2000 =(3550∗100)%=70%
  \begin{aligned}
  \text{for 1996 =}\left(\frac{35}{25}*100 \right)\% \\
  = 140\% \\
  \text{for 1997 =}\left(\frac{40}{35}*100 \right)\% \\
  = 114.29\% \\
  \text{for 1998 =}\left(\frac{45}{35}*100 \right)\% \\
  = 128.57\% \\
  \text{for 1999 =}\left(\frac{35}{40}*100 \right)\% \\
  = 87.5\% \\
  \text{for 2000 =}\left(\frac{35}{50}*100 \right)\% \\
  = 70\% \\
  
  \end{aligned}
  So for 1996 the percentage is highest.