Average Problems and Solutions

  • 1. Average of 10 matches is 32, How many runs one should should score to increase his average by 4 runs.

    1. 70
    2. 76
    3. 78
    4. 80
    Answer :

    Option B

    Explanation:

    Average after 11 innings should be 36

    So, Required score = (11 * 36) - (10 * 32)
    = 396 - 320 = 76

  • 2. The average age of the mother and her six children is 12 years which is reduced by 5 years if the age of the mother is excluded. How old is the mother

    1. 40
    2. 41
    3. 42
    4. 43
    Answer :

    Option C

  • 3. Find the average of first 10 multiples of 7

    1. 35.5
    2. 37.5
    3. 38.5
    4. 40.5
    Answer :

    Option C

    Explanation:

    \begin{aligned}
    = \frac {7(1+2+3+...+10)}{10}
    \end{aligned}

    \begin{aligned}
    = \frac {7(10(10+1))}{10 \times 2}
    \end{aligned}

    \begin{aligned}
    = \frac {7(110)}{10 \times 2} = 38.5
    \end{aligned}

  • 4. Find the sum of first 30 natural numbers

    1. 470
    2. 468
    3. 465
    4. 463
    Answer :

    Option C

    Explanation:

    Sum of n natural numbers
    \begin{aligned}
    = \frac{n(n+1)}{2}
    \end{aligned}

    \begin{aligned}
    = \frac{30(30+1)}{2} = \frac{30(31)}{2} = 465
    \end{aligned}

  • 5. Average of all prime numbers between 30 to 50

    1. 37
    2. 37.8
    3. 39
    4. 39.8
    Answer :

    Option D

    Explanation:

    Prime numbers between 30 and 50 are:
    31, 37, 41, 43, 47

    Average of prime numbers between 30 to 50 will be
    \begin{aligned}
    (\frac{31+37+41+43+47}{5}) = \frac{199}{5} = 39.8
    \end{aligned}

  • 6. Find the average of all numbers between 6 and 34 which are divisible by 5

    1. 15
    2. 20
    3. 25
    4. 30
    Answer :

    Option B

    Explanation:

    \begin{aligned}
    Average = (\frac{10+15+20+25+30}{5}) = \frac{100}{5} =20
    \end{aligned}

  • 7. Average of first five multiples of 3 is

    1. 9
    2. 11
    3. 13
    4. 15
    Answer :

    Option A

    Explanation:

    \begin{aligned}
    Average = \frac{3(1+2+3+4+5)}{5} = \frac{45}{5} = 9
    \end{aligned}

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